Triangle With Angle with Solution

 

Triangle With Angle:

Problem Description:

You're given the three angles a, b, and c respectively. Now check if these three angles can form a valid triangle with an area greater than 0 or not. Print "YES"(without quotes) if it can form a valid triangle with an area greater than 0, otherwise print "NO" (without quotes).

Input:

·       First-line will contain three numbers a, b, and c separated by space.

Output:

Print "YES"(without quotes) if these sides can form a valid triangle, otherwise, print "NO" (without quotes).

Constraints

·       0≤a,b,c≤180

Sample Input 1:

            20 40 120

Sample Output 1:

            YES

Sample Input 2:

            100 18 42

Sample Output 2:

            NO

EXPLANATION:

·       In the first example, angles set (20, 40, 120) can form a triangle with an area greater than 0.

·       In the second example, angles set (100, 18, 42) will never form a valid triangle.

Solution:

C++:

#include <iostream>
using namespace std;
int main()
{
    int a, b, c;
    cin >> a >> b >> c;
    if ((a + b + c) == 180 && a > 0 && b > 0 && c > 0)
        cout << "YES";
    else
        cout << "NO";
    return 0;
}

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