Armstrong Number in C

Program in C to check Armstrong Number

Armstrong Number: When a number is equal to the sum of the cube of each digit, then it is called an Armstrong Number.

Example: Number 153 is Armstrong number because:

  1             5            3

= 1*1*1 + 5*5*5 + 3*3*3

=    1     +  125   +   27

=   153 = Number, Hence it is Armstrong number.
The numbers 0, 1, 153, 370, 371 and 407 are some of the Armstrong numbers

s.

There are various ways to check whether a number is Armstrong or not. The General algorithm for the program is given below :

 Algorithm :

Step 1: Accept a number.

Step 2: Extract each digit and cube it and add it to a variable say sum.

Step 3

 If the sum is equal to a number then display that the number is Armstrong

else display that the number is not Armstrong.

Step 3: Stop

Code 1 :

#include < stdio.h >
int main()
{
    int number, numberCopy, sum = 0;
    printf(" Enter number here : ");
    scanf("%d", &number);
    numberCopy = number;
    while (numberCopy > 0)
    {
        int lastDigit = numberCopy % 10;
        int cubeOfLastDigit = lastDigit * lastDigit * lastDigit;
        sum = sum + cubeOfLastDigit;
        numberCopy = numberCopy / 10;
    }
    if (sum == number)
        printf(" The given number %d is an Armstrong Number ", number);
    else
        printf(" The given number %d is not an Armstrong Number ", number);
    return 0;
}

Code 2 :

#include <stdio.h>
#include <math.h>
int main()
{
    int number, n, sum = 0;
    printf(" Enter number here : ");
    scanf("%d", &number);
    n = number;
    while (n > 0)
    {
        sum = sum + pow(n % 10, 3);
        n = n / 10;
    }
    if (sum == number)
        printf(" The given number %d is an Armstrong Number ", number);
    else
        printf(" The given number %d is not an Armstrong Number ", number);
    return 0;
}

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